Eduardo, if this were simply a resistor, and if it were to fail, why then do some of these engines continue to run when the ignition supply is cut?
A resistor allows for bi-directional DC current flow.
A failing diode is more likely to allow reverse flow of DC current that keeps the ignition engergized!
Yes/No?
A dioded replacement has done the trick for me several times.
I'm open to learning more on this!
Diodes are normally nominated in Voltage. In short the Voltage it is capable of blocking. On the other hand all diodes has a certain leakage, normally in %. If you choose a diode with too high voltage, the leakage might be too high, and engine keeps running.
A diode normally fails in the way that it shorts, current goes both ways.
On the other hand if a lower voltage diode shorts, the amps going to the engine might not be enough to operate the coil, it will work almost as a resistor.
The 'European' system uses a 3W bulb as resistor, if remembering right. That gives about 0,3 Amps, enough to get the alternator started, but not to feed the coil. When that burns off, alternator will not start when engine is started, but engine will stop normally by the key. Engine will consume from batteries and stop when voltage gets too low.
The original US resistor is designed to short out when it fails. Alternator will start charging, but engine will not stop or drain the batteries.
I have seen all kinds of solutions to 'fix' this problem.
Light bulbs in engine room, manual switch on instrument panel, you name it.